A 0.145 kg baseball pitched at 35.0 m/s is hit on a horizontal line drive straight back toward the pitcher at 52.0 m/s. If the contact time between bat and ball is 1.00*10 to the -3, calculate the average force between the ball and bat during contact.
3.14 m/s
2465
12
To calculate the average force between the ball and bat during contact, we can use Newton's second law of motion, which states that force (F) equals mass (m) multiplied by acceleration (a): F = m * a.
In this case, we know the mass (m) of the baseball is 0.145 kg. However, we need to determine the acceleration (a) during contact.
To find the acceleration, we can use the equation for average acceleration: a = (v_f - v_i) / t.
Where:
- v_f is the final velocity of the baseball (52.0 m/s)
- v_i is the initial velocity of the baseball (35.0 m/s)
- t is the contact time between the bat and ball (1.00 × 10^(-3) s)
Substituting the given values into the equation, we have: a = (52.0 m/s - 35.0 m/s) / (1.00 × 10^(-3) s).
Calculating this, we get: a = 17.0 m/s / (1.00 × 10^(-3) s) = 1.70 × 10^4 m/s².
Now that we have the mass (m = 0.145 kg) and acceleration (a = 1.70 × 10^4 m/s²), we can calculate the average force (F) using Newton's second law: F = m * a.
Substituting the values, we get: F = 0.145 kg * 1.70 × 10^4 m/s².
Calculating this, we find: F = 2.465 N.
Therefore, the average force between the ball and bat during contact is approximately 2.465 Newtons.