A water bed that is 1.5 m wide and 2.5 m long weighs 1055 N. Assuming the entire lower surface of the bed is in contact with the floor, what is the pressure the bed exerts on the floor?

(Round to the first decimal point and don't forget units.

280 Pa

To find the pressure the bed exerts on the floor, we can use the formula for pressure:

Pressure = Force / Area

In this case, the force is the weight of the water bed, which is 1055 N. The area is the entire lower surface of the bed, which is equal to its width multiplied by its length.

Width = 1.5 m
Length = 2.5 m

Area = Width × Length

Substituting the values we have:

Area = 1.5 m × 2.5 m

Now we can calculate the area:

Area = 3.75 m²

Finally, we can substitute the values of force and area into the pressure formula:

Pressure = 1055 N / 3.75 m²

Calculating the pressure:

Pressure = 281.33 Pa

Therefore, the pressure the bed exerts on the floor is approximately 281.3 Pa (Pascal).

To calculate the pressure exerted by the water bed on the floor, we can divide the weight of the water bed by the area of the lower surface in contact with the floor.

Given:
Width of the water bed = 1.5 m
Length of the water bed = 2.5 m
Weight of the water bed = 1055 N

To find the area of the lower surface, we multiply the width by the length:
Area = Width × Length
Area = 1.5 m × 2.5 m
Area = 3.75 m²

Now, we can calculate the pressure:
Pressure = Weight / Area
Pressure = 1055 N / 3.75 m²

Calculating the pressure, we get:
Pressure ≈ 281.33 Pa

Therefore, the water bed exerts a pressure of approximately 281.3 Pa on the floor.