# Physics

A cube of wood with a density of 0.780 g/cm3 is 10.0 cm on each side. When the cube is placed in water, what buoyant force acts on the wood? (ρw = 1.00 g/cm3)

a. 5.00 N
b. 6.40 N
c. 7.65 N
d. 7.65 x 10^3 N

1. Fg/Fb=p(row)(object)/p(fluid)

9.81/Fb=.78/1

=7.65 N

posted by Ben

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