A horizontal force of magnitude 33.5 N pushes a block of mass 3.80 kg a distance of 3.00 m across a floor, where the coefficient of kinetic friction is 0.600.

(a) How much work is done by that applied force on the block-floor system?

Work done is force x distance, regardless of what the mass and friction is.

The answer is 33.5 * 3.00 = 100.5 Joules

To find the amount of work done by the applied force on the block-floor system, we need to multiply the magnitude of the force by the displacement of the block in the direction of the force.

Work (W) = Force (F) × Displacement (d) × cosθ

In this case, the force (F) is the horizontal force of magnitude 33.5 N, and the displacement (d) is 3.00 m. However, we need to determine the angle (θ) between the force and the displacement.

Since the force is applied horizontally and the displacement is also horizontally, the angle between them is 0° or 180°. We can choose either value, as the cosine of both angles is the same.

Let's calculate the work done using the formula:

W = (33.5 N) × (3.00 m) × cos0°

The cosine of 0° is 1, so the equation simplifies to:

W = (33.5 N) × (3.00 m) × 1

W = 100.5 N·m

Therefore, the work done by the applied force on the block-floor system is 100.5 Joules (J).