3.429 X2 (SO4)3 contains 0.12 mol of oxygn tom.what is the atomic wight of x?
To find the atomic weight of X, we need to use the information given in the chemical formula and the molar mass of the compound.
The compound 3.429 X2(SO4)3 contains 0.12 mol of oxygen atoms.
To calculate the atomic weight of X, we can follow these steps:
Step 1: Calculate the molar mass of (SO4)3.
The molar mass of (SO4)3 can be calculated by adding up the atomic masses of the individual atoms.
The atomic mass of sulfur (S) is 32.06 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol.
So, the molar mass of (SO4)3 = (32.06 + (16.00 x 4)) x 3 = 342.16 g/mol.
Step 2: Calculate the number of moles of (SO4)3 in the compound.
We have 0.12 mol of oxygen atoms, and each (SO4)3 molecule contains 3 oxygen atoms.
So, the number of moles of (SO4)3 = (0.12 mol) / (3 mol) = 0.04 mol.
Step 3: Calculate the total mass of (SO4)3 in the compound.
The total mass of (SO4)3 = (molar mass) x (number of moles) = 342.16 g/mol * 0.04 mol = 13.6864 g.
Step 4: Calculate the molar mass of X.
Since we have two X atoms in each (SO4)3 molecule, we can divide the total mass of (SO4)3 by 2 to get the molar mass of X.
Molar mass of X = (total mass of (SO4)3) / 2 = 13.6864 g / 2 = 6.8432 g/mol.
Therefore, the atomic weight of X is approximately 6.8432 g/mol.