Correction of problem submiited earlier.
The amount P of pollution varies directly with the population N of people. City A has a population of 494,000 and produces 260,000 tons of pollutants. Find how many tons of pollution we should except City B to produce if population is 344,000. Do not round until final answer, then round to nearest ton as needed
Is "except" supposed to be "expect".
OK, so P = C N where C is a constant
This implies
Pb/Pa = Nb/Na
The subcripts denote cities A or B
Pb = Pa*(Nb/Na)
= 260,000*(344/494)= 181,053 tons
it is expect. thanks
To solve this problem, we need to use the concept of direct variation. In direct variation, two quantities are related in such a way that they multiply to give a constant value.
Let's denote the constant of variation as k. In this case, the amount of pollution (P) varies directly with the population (N), so we have:
P = kN
We are given that City A has a population of 494,000 and produces 260,000 tons of pollutants. We can use this information to find the value of k.
260,000 = k * 494,000
To solve for k, divide both sides of the equation by 494,000:
k = 260,000 / 494,000
k ≈ 0.5263
Now we can use this value of k to find the amount of pollution expected in City B, given its population of 344,000.
P = kN
P = 0.5263 * 344,000
P ≈ 180,871.2
So, we should expect City B to produce approximately 180,871.2 tons of pollution. Rounded to the nearest ton, the answer is 181 tons.