Factor completely or state that this is prime (cannot be factored)
2y^4 + 28y^3 + 98y^2
Note: x^2 is x-squared (that is, x with the superscript 2), etc.
2y^4 + 28y^3 + 98y^2 = 2 y^2 (y^2 + 14 y + 49)
The last expression (in parentheses) is a perfect square, and can be factored again. See if you can finish it.
2y^2[(y = 7)]^2
Is that right?
If you change the = sign to a + sign (an obvious typo), yes, that is right.
Thank you
You're welcome! Just to clarify, the correct expression is:
2y^4 + 28y^3 + 98y^2 = 2 y^2 (y^2 + 14 y + 49)
The last expression (in parentheses) is indeed a perfect square, and it can be further factored as:
2 y^2 (y + 7)^2
So, the completely factored form of the given expression is:
2y^2 (y + 7)^2
Again, you did a great job! Let me know if there's anything else I can help with.