How do you properly solve _ Ag + _ Cu(Nu3)2 ---> _ AgNo3 + _ Cu
1. Start by writing the correct letters.
2. You have two nitrates on the left so make that 2AgNO3 on the right.
Ag + Cu(NO3)2 ==> 2AgNO3 + Cu
3. Now you have 2 Ag on the right, make that 2 Ag on the left.
2Ag + Cu(NO3)2 --> 2AgNO3 + Cu
To solve a chemical equation, you need to balance the equation by ensuring that the number of atoms of each element is equal on both sides of the equation.
Here's a step-by-step method to balance the given equation:
1. Write down the unbalanced equation: "_ Ag + _ Cu(NO3)2 → _ AgNO3 + _ Cu"
2. Count the number of atoms of each element on both sides of the equation:
- Ag: 1 Ag on the left, 1 Ag on the right
- Cu: 1 Cu on the left, 1 Cu on the right
- N: 6 N on the left (2 in Cu(NO3)2 and 4 in NO3), 1 N on the right (in AgNO3)
- O: 8 O on the left (6 in Cu(NO3)2 and 2 in NO3), 3 O on the right (in AgNO3)
3. Start balancing the equation by adjusting the coefficients (numbers in front) of each compound. Begin with the most complex molecule, Cu(NO3)2.
Cu(NO3)2: The number of Cu atoms is already balanced, so let's balance the nitrate (NO3) groups.
Since there are 2 NO3 groups in Cu(NO3)2 on the left side and only 1 NO3 group on the right side, add a coefficient of 2 in front of AgNO3: "_ Ag + _ Cu(NO3)2 → 2 AgNO3 + _ Cu"
4. Continue balancing by adjusting coefficients for the remaining compounds:
Ag: There is 1 Ag on the left and 2 Ag groups on the right. Add a coefficient of 2 in front of Ag on the left: "2 Ag + _ Cu(NO3)2 → 2 AgNO3 + _ Cu"
Cu: There is 1 Cu on the left and 1 Cu on the right. No further changes needed.
5. Finally, check and balance the number of nitrogen and oxygen atoms:
- Nitrogen: There are still 6 N on the left (2 in Cu(NO3)2 and 4 in AgNO3), and now 6 N on the right (in 2 AgNO3).
- Oxygen: There are now 12 O on the left (6 in Cu(NO3)2 and 6 in AgNO3), and 12 O on the right (in 2 AgNO3).
The balanced equation is:
2 Ag + Cu(NO3)2 → 2 AgNO3 + Cu