Solve for c.
A=-3(a=b-1/3c)
There can be no = sign within parentheses. What did you really man to write?
Also: Is the c meant to be in the denominator with the last 3?
Since + is shift=, I'll guess it's supposed to be
A = -3(a + b - 1/3 c)
-A/3 = a + b - 1/3 c
-(A/3 + a + b) = -c/3
c = A + 3a + 3b
To solve for "c" in the given equation:
A = -3(a = b - 1/3c)
First, let's simplify the equation:
Multiply through the parentheses to remove them:
A = -3a = -3b + c
Next, isolate the term with "c" on one side of the equation by moving the other terms to the opposite side:
A + 3b = c
So, the equation simplifies to:
c = A + 3b
Therefore, "c" is equal to the sum of "A" and 3 times "b".