The base of an isosceles triangle is 4/3 cm.the perimeter of the triangle is 4 2/15cm. What is the length of either of the remaining equal sides
4 2/15 = 4/3 + 2x
2x = 62/15 -4/3 = 62/15 - 20/15
= 32/15
x= 16/15 = 1 1/15 cm
1_2/5
To find the length of the equal sides of an isosceles triangle, we need to use the information given about the base and the perimeter.
Let's denote the length of either of the remaining equal sides as x cm.
The perimeter of a triangle is the sum of all its side lengths. In this case, we are given that the perimeter is 4 2/15 cm. We can write this as a mixed fraction: 4 2/15 = 62/15 cm.
The perimeter of an isosceles triangle is given by the formula P = 2s + b, where P is the perimeter, s is the length of an equal side, and b is the length of the base.
Substituting the given values into the formula, we get 62/15 = 2x + 4/3.
Now, let's solve the equation to find the value of x.
To do that, we can first simplify the equation by multiplying both sides by 15 to get rid of the fraction:
(62/15) * 15 = (2x + 4/3) * 15
62 = 30x + 20/3
Next, let's simplify the equation further by multiplying both sides by 3 to eliminate the fraction:
3 * 62 = 3 * (30x + 20/3)
186 = 90x + 20
Now, we can isolate the variable x by subtracting 20 from both sides:
186 - 20 = 90x + 20 - 20
166 = 90x
Finally, divide both sides by 90 to solve for x:
166 / 90 = 90x / 90
1.844 = x
Therefore, the length of either of the remaining equal sides of the isosceles triangle is approximately 1.844 cm.