A 1 kg object requires 10 N of force to lift it 5 m from the bottom of a well. (use g = 10 m/s2)
What is the kinetic energy when the object has fallen halfway down the well (2.5m)?
To determine the kinetic energy of an object halfway down the well, we can use the conservation of energy principle, which states that the total energy of a system remains constant.
First, let's calculate the potential energy of the object at the top of the well (5 m above the bottom):
Potential Energy = m * g * h
where:
m = mass of the object = 1 kg
g = acceleration due to gravity = 10 m/s^2
h = height above the bottom = 5 m
Potential Energy = 1 kg * 10 m/s^2 * 5 m = 50 J
Since the potential energy is converted into kinetic energy as the object falls, we can use the conservation of energy principle to find the kinetic energy halfway down (2.5 m above the bottom):
Kinetic Energy + Potential Energy = Total Energy
At the top of the well, the total energy is equal to the potential energy:
Total Energy = 50 J
So, at the halfway point, the kinetic energy can be determined as:
Kinetic Energy = Total Energy - Potential Energy
= 50 J - 50 J
= 0 J
Therefore, when the object is halfway down the well (2.5 m above the bottom), its kinetic energy is zero.
PEchange=KE change
mgh-mg(h/2)=KE
solve for KE