Julie carries an 8.0-kg suitcase as she walks 18 m along an inclined walkway to her hotel room at a constant speed of 1.5 m/s. The walkway is inclined 15 degrees above the horizontal. How much work does Julie do in carrying her suitcase?
W=Fcos(th)s
where F is force, th is the angle between the displacement and the force, and s is the displacement.
recall
F=ma
since her speed is constant,
a=0
therefore
F=0
therefore
W=0
zero joules
18m*sin15* M * g = ___ J
That does not count her work carrying herself, which is much more.
Her speed does not matter. That information is there to fool you.
To find the amount of work Julie does in carrying her suitcase, we need to use the formula:
Work = force * distance * cos(theta)
Where:
- force is the force applied to the suitcase, which is the weight of the suitcase.
- distance is the distance Julie walks with the suitcase.
- theta is the angle between the force direction and the displacement direction.
First, let's find the force applied to the suitcase, which is its weight. The weight is given by the formula:
Weight = mass * acceleration due to gravity
The mass of the suitcase is given as 8.0 kg, and the acceleration due to gravity is approximately 9.8 m/s^2. So, the weight of the suitcase is:
Weight = 8.0 kg * 9.8 m/s^2
Now, let's find the distance Julie walks with the suitcase, which is given as 18 m.
Finally, we need to find the angle theta between the force and displacement directions. In this case, the angle is the inclination of the walkway, which is given as 15 degrees.
Now, we can substitute the values into the formula:
Work = (8.0 kg * 9.8 m/s^2) * 18 m * cos(15 degrees)
Simplifying this equation will give us the amount of work Julie does in carrying her suitcase.