Point M is the midpoint of AC. Find its coordinates. (1 point)(b + c, d)
(a + c, d)
(2c + 2c, d)
(2b + c, d)
2. Point N is the midpoint of BC. Find its coordinates. (1 point)(b + c, d)
(a + c, d)
(2a + c, d)
What theorem do Exercises 1-4 prove? (1 point)Triangle Inequality Theorem
Converse of the Angle Bisector Theorem
Angle Bisector Theorem
Triangle Midsegment Theorem
To find the coordinates of the midpoint M, we need to take the average of the x-coordinates and the average of the y-coordinates of the points A and C.
Let's say the coordinates of A are (a, d) and the coordinates of C are (c, d).
The x-coordinate of the midpoint M is given by (a + c)/2, and the y-coordinate is simply d.
So the coordinates of M are (a + c)/2, d.
Therefore, the correct answer is (a + c, d).
Similarly, to find the coordinates of the midpoint N, we need to take the average of the x-coordinates and the average of the y-coordinates of the points B and C.
Let's say the coordinates of B are (b, d).
The x-coordinate of the midpoint N is given by (b + c)/2, and the y-coordinate is simply d.
So the coordinates of N are (b + c)/2, d.
Therefore, the correct answer is (b + c, d).
As for the theorem being proven by exercises 1-4, it is the Triangle Midsegment Theorem.