For the balanced equation shown below, how many moles of O2 will REACT with 0.6614 moles of NO?
2NO+O2 --> 2NO2
See your post above.
To determine the number of moles of O2 that will react with 0.6614 moles of NO, we need to use the stoichiometry of the balanced equation.
The balanced equation tells us that 2 moles of NO react with 1 mole of O2 to produce 2 moles of NO2.
Based on this stoichiometry, we can set up a proportion to find the number of moles of O2:
(2 moles of NO) / (1 mole of O2) = (0.6614 moles of NO) / (x moles of O2)
We can cross-multiply and solve for x:
2 moles of NO = (0.6614 moles of NO) * (1 mole of O2) / (x moles of O2)
2 moles of NO = 0.6614 moles of NO / x moles of O2
Now, we can solve for x by isolating it:
2 moles of NO * x moles of O2 = 0.6614 moles of NO * 1 mole of O2
2x = 0.6614
x = 0.6614 / 2
x = 0.3307 moles of O2
Therefore, 0.3307 moles of O2 will react with 0.6614 moles of NO.