V=12.3L, P=1.0 atm, T=300K. The piston on the cylinder is pushed until the volume is 6.0 liters. If the temperature remains constant, what is the new pressure of the N2(g)?

I got 2.05atm

P1V1 = P1V2

Solve for P2.

234 To find the new pressure of N2(g), we can use Boyle's Law, which states that for an ideal gas at constant temperature, the pressure and volume are inversely proportional.

Boyle's Law equation: P1 * V1 = P2 * V2

Given:
Initial volume (V1) = 12.3 L
Initial pressure (P1) = 1.0 atm
Final volume (V2) = 6.0 L
Temperature (T) remains constant

Using Boyle's Law equation, we can rearrange it to solve for the final pressure (P2):

P2 = (P1 * V1) / V2
P2 = (1.0 atm * 12.3 L) / 6.0 L

Now, let's substitute the given values into the equation:

P2 = (1.0 atm * 12.3 L) / 6.0 L
P2 = 12.3 atm / 6.0 L
P2 ≈ 2.05 atm

Therefore, the new pressure of N2(g) is approximately 2.05 atm.