The first 1/5 of a mile is $1.50. For every additional 1/5 of a mile is 25 cents. If Marc has $3.75, at least how far can he go?

P.S. I need an inequality.

To solve this problem and find the minimum distance Marc can go, we need to set up an inequality based on the given information.

Let's start by breaking down the cost equation. The first 1/5 of a mile costs $1.50, and every additional 1/5 of a mile costs 25 cents. We can express this relationship using the following equation:

Cost = $1.50 + 0.25 * (x - 1/5)

Where x represents the number of 1/5 of a mile increments beyond the first 1/5 of a mile.

Now, we want to find the maximum value of x that can be achieved with a cost of $3.75 or less. Thus, we can write the inequality as:

$1.50 + 0.25 * (x - 1/5) ≤ $3.75

To simplify the inequality, let's first distribute the 0.25:

$1.50 + 0.25x - 0.05 ≤ $3.75

Combine like terms:

0.25x + 1.45 ≤ $3.75

Finally, let's subtract 1.45 from both sides to isolate the variable:

0.25x ≤ $3.75 - 1.45
0.25x ≤ $2.30

Now, to solve for x, divide both sides by 0.25:

x ≤ $2.30 / 0.25
x ≤ 9.2

Since x represents the number of 1/5 of a mile increments, we need to disregard the fractional part of 9.2. Thus, Marc can go at most 9 increments beyond the first 1/5 of a mile.

So the minimum distance Marc can go is 1/5 + 9/5 = 10/5 = 2 miles.

Therefore, the inequality that represents this scenario is:
x ≤ 9
or
Number of 1/5 of a mile increments (x) is less than or equal to 9.