4x+y<0
(P.S. The "<" sign has a line underneath it, which means greater than or equal to..?)
Please help, thaaanks.c:
Y < 4x so
when x = 1 then y <4
when x = 2 then y <8
when x = 3 then y < 12
....
What about the 0?
Issy, two points. that signmeans less than or equal to.
Secondly,
4x+y<=0
subtract 4x from each side.
y<=-4x+0
the zero identity principle leads to
y<=-4x
If x=1, then y<=-4
and so on
Sure, I can help you with that inequality.
The inequality 4x + y < 0 represents a linear inequality in two variables, x and y. It indicates that any point (x, y) that satisfies the inequality will lie beneath the graph of the corresponding line.
To determine which points (x, y) satisfy the inequality, you can start by considering points that lie on the boundary line, which is formed when we replace the inequality symbol "<" with an equal sign "=".
To find the equation of the boundary line, substitute the "=" sign instead of "<" in the original inequality:
4x + y = 0
Now we have the equation of the boundary line. To graph it, we need to find two points that lie on the line.
One way to find these points is to set x = 0 and solve for y:
4(0) + y = 0
y = 0
So, one point on the line is (0, 0).
Next, set y = 0 and solve for x:
4x + 0 = 0
4x = 0
x = 0
So, another point on the line is (0, 0).
Since both points are the same, the boundary line is the line passing through the origin (0, 0).
Now, to determine which side of the line satisfies the original inequality, you can choose any test point not on the line (0, 0) and substitute its x and y values into the inequality to see if it is true or false.
For example, let's choose the point (1, 1) as a test point to see if it satisfies the inequality:
4(1) + 1 < 0
4 + 1 < 0
5 < 0
Since 5 is NOT less than 0, the point (1, 1) does not satisfy the inequality. Therefore, the region below the line (excluding the line itself) represents the set of points that satisfy the inequality.
In summary, the solution to the inequality 4x + y < 0 is the area below the line 4x + y = 0 when graphed on a coordinate plane.