What Temperature would you get after the First 5 Minutes of Putting 4 Ices into a 99 degree warm water? After The Second 5 MInutes? YOu Might need to do this experiment at home. But May anyone Please Help and tell me it in Farenheit so i can confirm my Answers.

Have you done this experiment as your teacher asked?

yes...

but i got the degrees but i am not surely positive and i would right it online. But i don't wnat someone to be like 'oh your answer is correct' and just agree with me just because i wrote it. I hope you can understand what i am saying

I understand what you're saying.

I can't confirm your answer without doing this experiment myself. Sorry, I won't do this. Just turn in the answer you got.

To calculate the temperature of the water after placing ice cubes in it, we need to consider the principles of heat transfer. The ice cubes will absorb heat from the warm water until they reach their melting point. Then, they will continue to absorb heat and melt while the water temperature decreases.

Here's a step-by-step explanation of how you can calculate the temperature:

1. Identify the initial conditions:
- Initial water temperature = 99°F
- Number of ice cubes = 4
- Each ice cube's temperature = 0°F (freezing point)

2. Determine the heat transfer:
- The ice cubes will absorb heat from the water until they reach their melting point.
- This is calculated using the specific heat capacity equation: Q = mcΔT.
- Q is the heat transferred.
- m is the mass of the ice.
- c is the specific heat capacity of ice (0.5 cal/g°C approximately).
- ΔT is the change in temperature.
- Since we're interested in temperature, we can rearrange the equation to find ΔT: ΔT = Q / (mc).
- Assume the mass of each ice cube is 15 grams.

3. Calculate ΔT for the first 5 minutes:
- In the first 5 minutes, the ice cubes will absorb heat until they melt completely.
- The heat transferred can be calculated as: Q = m * c * ΔT.
- Since the ΔT is unknown (what we want to find), it can be simplified as: Q = m * c * ΔT = m * L.
- Here, L is the heat of fusion (latent heat) of ice, which is 80 cal/g.
- Substituting the values, we get: 80 cal/g = 15 g * ΔT.
- Therefore, ΔT = 80 cal / (15 g) ≈ 5.3°C (or 9.5°F).

4. Calculate the final temperature after the ice melts for the first 5 minutes:
- The final temperature will be the initial water temperature minus the change in temperature caused by the melting ice cubes.
- Final temperature = 99°F - 9.5°F ≈ 89.5°F.

5. Repeat steps 3 and 4 for the second 5 minutes:
- The ΔT for the second 5 minutes will be zero since the ice has already melted.
- Therefore, the final temperature will remain the same: 89.5°F.

So, the approximate temperatures you would get after the first and second 5 minutes are 89.5°F.