The velocity of a diver just before hitting the water is -11.1 m/s, where the minus sign indicates that her motion is directly downward. What is her displacement during the last 1.18 s of the dive?
To find the displacement of the diver during the last 1.18 seconds of the dive, we need to know the initial velocity, final velocity, and the time interval.
Given:
Initial velocity (u) = 0 m/s (since it is not provided, we assume the diver starts from rest)
Final velocity (v) = -11.1 m/s (negative indicates downward)
Time (t) = 1.18 s
We can use the constant acceleration equation:
Displacement (s) = (v + u) * t / 2
Substituting the values:
s = (-11.1 m/s + 0 m/s) * 1.18 s / 2
Calculating:
s = -6.55 m
Therefore, the displacement of the diver during the last 1.18 seconds of the dive is -6.55 meters. The negative sign indicates that the displacement is in the downward direction.