a truck is moving 15m/s North. after 7.9 has elapsed it is moving 55m/s North. determine the truck's acceleration and determine its displacement during the elapsed time.
To determine the truck's acceleration, we can use the formula:
Acceleration (a) = (Final Velocity - Initial Velocity) / Time
Given:
Initial velocity (u) = 15 m/s
Final velocity (v) = 55 m/s
Time (t) = 7.9 s
Let's substitute these values into the formula:
Acceleration (a) = (55 m/s - 15 m/s) / 7.9 s
= 40 m/s / 7.9 s
≈ 5.06 m/s²
Therefore, the truck's acceleration is approximately 5.06 m/s².
To determine the truck's displacement during the elapsed time, we can use the formula:
Displacement (s) = Initial Velocity * Time + 0.5 * Acceleration * Time²
Given:
Initial velocity (u) = 15 m/s
Time (t) = 7.9 s
Acceleration (a) = 5.06 m/s²
Substituting these values into the formula:
Displacement (s) = 15 m/s * 7.9 s + 0.5 * 5.06 m/s² * (7.9 s)²
= 118.5 m + 0.5 * 5.06 m/s² * 62.41 s²
= 118.5 m + 158.4 m
= 276.9 m
Therefore, the truck's displacement during the elapsed time of 7.9 seconds is 276.9 meters.