What mass of hydrogen peroxide should result when 1.50g of barium peroxide is reacted with 25.0mL of 0.50 M hydrochloric acid?
To determine the mass of hydrogen peroxide formed, we need to calculate the limiting reagent. The limiting reagent is the reactant that is completely consumed in the reaction, thereby determining the maximum amount of product that can be formed.
Step 1: Write the balanced chemical equation for the reaction:
BaO2 + 2HCl -> BaCl2 + H2O2
Step 2: Calculate the number of moles of barium peroxide (BaO2):
Molar mass of BaO2 = 169.34 g/mol
Number of moles = mass / molar mass
Number of moles = 1.50 g / 169.34 g/mol = 0.00886 mol
Step 3: Calculate the number of moles of hydrochloric acid (HCl):
Molarity (M) = moles / volume (L)
Number of moles = Molarity x Volume (L)
Number of moles = 0.50 mol/L x 0.025 L = 0.0125 mol
Step 4: Determine the stoichiometry ratio of reaction between barium peroxide and hydrogen peroxide:
From the balanced equation, 1 mole of BaO2 produces 1 mole of H2O2.
Therefore, 0.00886 mol of BaO2 will produce 0.00886 mol of H2O2.
Step 5: Convert moles of hydrogen peroxide to mass:
Molar mass of H2O2 = 34.02 g/mol
Mass of H2O2 = number of moles x molar mass
Mass of H2O2 = 0.00886 mol x 34.02 g/mol = 0.301 g
Therefore, the mass of hydrogen peroxide formed is 0.301 grams.
To determine the mass of hydrogen peroxide produced in the reaction, we need to first write and balance the chemical equation for the reaction between barium peroxide (BaO2) and hydrochloric acid (HCl). The balanced equation is as follows:
BaO2 + 2HCl -> BaCl2 + H2O2
From the equation, we can see that 1 mole of barium peroxide reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen peroxide.
Step 1: Convert the mass of barium peroxide to moles.
We are given the mass of barium peroxide, which is 1.50g. To convert this mass to moles, we need to divide it by the molar mass of barium peroxide, which is 169.34 g/mol.
moles of BaO2 = mass of BaO2 / molar mass of BaO2
moles of BaO2 = 1.50g / 169.34 g/mol
Step 2: Calculate the moles of hydrogen peroxide.
Since 1 mole of barium peroxide produces 1 mole of hydrogen peroxide, the moles of hydrogen peroxide produced will be the same as the moles of barium peroxide.
moles of H2O2 = moles of BaO2 = 1.50g / 169.34 g/mol
Step 3: Convert moles of hydrogen peroxide to mass.
To convert the moles of hydrogen peroxide to mass, we multiply the moles by the molar mass of hydrogen peroxide, which is 34.02 g/mol.
mass of H2O2 = moles of H2O2 * molar mass of H2O2
mass of H2O2 = (1.50g / 169.34 g/mol) * 34.02 g/mol
By calculating this expression, we will find the mass of hydrogen peroxide produced in the reaction between barium peroxide and hydrochloric acid.
Here is a worked example of a stoichiometry problem. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html