Zinc reacts with HCl to produce ZnCl2 and Hydrogen gas, H2. What volume, in ml of a 1.25 M solution would be required to completely react with 3.27 g of Zn?

Zn(s) + 2 HCl (aq) -------> ZnCl2 + H2

To determine the volume of a 1.25 M HCl solution required to react with 3.27 g of Zn, we can use the following steps:

Step 1: Calculate the moles of Zn using its molar mass.
Step 2: Determine the moles of HCl required using the stoichiometric ratio between Zn and HCl.
Step 3: Convert the moles of HCl to volume using its molarity.

Let's calculate it step by step:

Step 1: Calculate the moles of Zn.
The molar mass of Zn is 65.38 g/mol.
Moles of Zn = mass / molar mass
= 3.27 g / 65.38 g/mol
≈ 0.05 mol

Step 2: Determine the moles of HCl required using the stoichiometric ratio.
From the balanced equation, we can see that 1 mole of Zn reacts with 2 moles of HCl.
Moles of HCl = 2 * moles of Zn
= 2 * 0.05 mol
= 0.1 mol

Step 3: Convert the moles of HCl to volume using its molarity.
Molarity (M) = moles / volume in liters
Volume in liters = moles / Molarity
= 0.1 mol / 1.25 mol/L
= 0.08 L

Since 1 L is equal to 1000 mL, the volume required in mL would be:
Volume in mL = Volume in liters * 1000
= 0.08 L * 1000
= 80 mL

Therefore, 80 mL of a 1.25 M HCl solution would be required to completely react with 3.27 g of Zn.

To find the volume of a 1.25 M HCl solution required to react with 3.27 g of Zn, we need to follow a few steps.

1. Determine the moles of Zn:
The molar mass of Zn is approximately 65.38 g/mol. Divide the given mass (3.27 g) by the molar mass to find the number of moles:
Moles of Zn = 3.27 g / 65.38 g/mol = 0.05 mol

2. Use the stoichiometry of the balanced equation to relate moles of Zn to moles of HCl:
From the balanced equation, we know that the ratio of moles of Zn to moles of HCl is 1:2. This means for every 1 mol of Zn, we need 2 moles of HCl.

3. Calculate the moles of HCl needed:
Moles of HCl = 2 * moles of Zn = 2 * 0.05 mol = 0.10 mol

4. Use the molarity of the HCl solution to find the volume:
The molarity (M) of a solution is defined as the number of moles of solute dissolved in 1 liter of solution. In this case, we have a 1.25 M solution, which means there are 1.25 moles of HCl in 1 liter of solution.

Volume of HCl solution (in liters) = Moles of HCl / Molarity
= 0.10 mol / 1.25 mol/L = 0.08 L

5. Convert the volume to milliliters (ml):
Since 1 L = 1000 ml, we can convert the volume from liters to milliliters by multiplying by 1000.

Volume of HCl solution (in ml) = 0.08 L * 1000 ml/L = 80 ml

Therefore, 80 ml of a 1.25 M HCl solution would be required to completely react with 3.27 g of Zn.

Convert 3.27 g Zn to moles. moles = grams/molar mass.

Using the coefficients in the balanced equation, convert moles Zn to moles HCl.

Then M = moles/L. You know moles and M, solve for L and convert to mL.