you need to make .80 M solution of NiSO4 (aq). How many grams of NiSO4 * 6H2O should you put into a .50 L volumetric flask?
You want how many moles?
That is M x L = 0.80 x 0.500L = ?
Then grams = moles/molar mass. You want to use the molar mass of NiSO4.6H2O
To determine the number of grams of NiSO4 * 6H2O needed to make a 0.80 M solution in a 0.50 L volumetric flask, we need to follow these steps:
Step 1: Understand the Problem
The problem states that we want to make a 0.80 M solution of NiSO4 (aq) in a 0.50 L volumetric flask. We need to find the mass of NiSO4 * 6H2O required to make this solution.
Step 2: Determine the Molar Mass
The molar mass of NiSO4 * 6H2O can be calculated by summing the molar masses of its constituent atoms. Looking up the atomic masses for nickel (Ni), sulfur (S), oxygen (O), and hydrogen (H):
M(Ni) = 58.69 g/mol
M(S) = 32.07 g/mol
M(O) = 16.00 g/mol
M(H) = 1.01 g/mol
Since there are six water molecules (H2O) in NiSO4 * 6H2O, we can add the molar mass of six water molecules (6 * 18.02 g/mol = 108.12 g/mol) to the molar mass of NiSO4.
M(NiSO4 * 6H2O) = (M(Ni) + M(S) + 4 * M(O)) + M(H2O) = (58.69 + 32.07 + 4 * 16.00) + 108.12 = 262.10 g/mol
The molar mass of NiSO4 * 6H2O is 262.10 g/mol.
Step 3: Calculate the Number of Moles
We know that the given concentration (0.80 M) is equal to the moles of solute divided by the volume of the solution in liters.
Molarity (M) = Moles (mol) / Volume (L)
Rearranging the equation, we can calculate the number of moles:
Moles (mol) = Molarity (M) * Volume (L)
Moles (mol) = 0.80 M * 0.50 L = 0.40 mol
Step 4: Determine the Mass
To find the mass of NiSO4 * 6H2O required, we can use the equation:
Mass (g) = Moles (mol) * Molar Mass (g/mol)
Mass (g) = 0.40 mol * 262.10 g/mol = 104.84 g
Therefore, you would need to put 104.84 grams of NiSO4 * 6H2O into the 0.50 L volumetric flask to make a 0.80 M solution.