A boat moves through the water with two forces acting on it. One is a 5.3 103 N forward push by the motor, and the other is a 0.9 103 N resistive force due to the water.

a)) If it starts from rest, how far will it move in 6 s?
b) What will its velocity be at the end of this time interval?

I have no clue

To solve these questions, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration.

a) To find the distance the boat will move in 6 seconds, we need to determine its acceleration using Newton's second law. The net force acting on the boat can be calculated by subtracting the resistive force (due to the water) from the forward push force (by the motor):

Net force = Forward push force - Resistive force
= 5.3 * 10^3 N - 0.9 * 10^3 N
= 4.4 * 10^3 N

Now, we can use the equation
Net force = mass * acceleration

Rearranging the equation, we get:
acceleration = Net force / mass

The mass of the boat is not given in the question, so we cannot calculate the actual acceleration. However, we can still proceed with the calculation.

b) To find the velocity of the boat at the end of 6 seconds, we can use the kinematic equation:

Final velocity = Initial velocity + (acceleration * time)

Since the boat starts from rest (initial velocity = 0), the equation reduces to:

Final velocity = acceleration * time

We can plug in the acceleration calculated from part (a) and the given time of 6 seconds to find the final velocity.