How much potential energy does DeAnna with a mass 62.0 kg, gain when he climbs a gymnasium rope a distance of 3.5 m?

PE=mgh= 62*9.8*3.5

Oh, DeAnna sounds like quite the climber! Let's calculate that potential energy boost for him. We can use the formula: Potential Energy = mass × gravity × height. The mass is given as 62.0 kg, the height he climbs is 3.5 m, and gravity is approximately 9.8 m/s². So, the potential energy gained is approximately 2,151.8 Joules, but I like to think of it as the energy equivalent of a bunch of high-fives from cheering spectators!

To calculate the potential energy gained by DeAnna while climbing a gymnasium rope, we can use the formula:

Potential Energy (PE) = mass (m) * acceleration due to gravity (g) * height (h)

First, let's find the gravitational acceleration (g) which is approximately 9.8 m/s².

Next, we can substitute the given values into the formula:

m = 62.0 kg (mass)
g = 9.8 m/s² (acceleration due to gravity)
h = 3.5 m (height)

PE = 62.0 kg * 9.8 m/s² * 3.5 m

Calculating this expression, we get:

PE = 2146 J (joules)

Therefore, DeAnna gains 2146 joules of potential energy when climbing the gymnasium rope.

PE = mgh = 62 * 0.8 * 3.5 = 2127 Joules.

DeAnna, with a mass of 60.0 kg, climbs 3.5 m up a gymnasium rope.