What are the products ?
CH3-CH2-CH2-CH3 + Br2à
The given chemical equation represents a reaction between a compound called butane (C4H10) and bromine (Br2). This reaction results in the substitution of a hydrogen atom in butane with a bromine atom, forming a product.
To determine the products of this reaction, we need to understand the mechanism of substitution reactions. In this case, bromine will react with butane to replace one of the hydrogen atoms attached to a carbon in the butane molecule.
The reaction involves a free radical substitution mechanism, where bromine molecules (Br2) are broken down into bromine radicals (Br·) by the addition of an initiation step (usually UV light or heat). The bromine radical then reacts with a butane molecule, replacing a hydrogen atom and forming a butyl radical (C4H9·). Finally, the butyl radical reacts with another bromine molecule, leading to the formation of the product.
The possible products in this reaction are different isomers of bromobutane. Isomers are compounds that have the same molecular formula but different structural arrangements. In this case, there are two possible isomers:
1. 1-bromobutane: In this isomer, the bromine atom replaces a hydrogen atom on the first (or primary) carbon of the butane chain. The resulting molecular formula for 1-bromobutane is C4H9Br.
2. 2-bromobutane: In this isomer, the bromine atom replaces a hydrogen atom on the second (or secondary) carbon of the butane chain. The resulting molecular formula for 2-bromobutane is also C4H9Br.
To find the specific isomer formed in the reaction, we would need additional information such as reaction conditions (temperature, solvent, etc.) and any possible regioselectivity or stereoselectivity.
It is important to note that the reaction might also form other brominated products, such as dibromobutanes or bromoalkenes, if side reactions occur.
To determine the exact products, experimental verification or further information is necessary.