Calculate the molarity of a solution prepared by diluting 200.0 mL of 4.0 M HCl to 500.0 mL of solution
a. 1.1 M
b. 1.6 M
c. 2.7 M
d. 10. M
c1v1 = c2v2
4x200=cx500
To calculate the molarity of the solution, you can use the formula:
M1V1 = M2V2
Where:
M1 = initial molarity
V1 = initial volume
M2 = final molarity
V2 = final volume
In this case, the initial molarity (M1) is 4.0 M, the initial volume (V1) is 200.0 mL, the final molarity (M2) is unknown, and the final volume (V2) is 500.0 mL.
Plugging these values into the formula, we have:
4.0 M x 200.0 mL = M2 x 500.0 mL
Simplifying this equation:
M2 = (4.0 M x 200.0 mL) / 500.0 mL
M2 = 1.6 M
Therefore, the molarity of the resulting solution is 1.6 M.
The correct answer is b. 1.6 M.
To calculate the molarity of a solution, you need to use the equation:
M1V1 = M2V2
where:
M1 = initial molarity (4.0 M)
V1 = initial volume (200.0 mL)
M2 = final molarity (unknown)
V2 = final volume (500.0 mL)
First, let's convert the initial and final volumes to liters:
V1 = 200.0 mL = 0.2 L
V2 = 500.0 mL = 0.5 L
Now, we can plug the values into the equation and solve for M2:
M1V1 = M2V2
(4.0 M)(0.2 L) = M2(0.5 L)
0.8 M = M2(0.5 L)
M2 = 0.8 M / 0.5 L = 1.6 M
Therefore, the molarity of the solution after dilution is 1.6 M. So, the correct answer is option b.