The length of the top of a table is 4m greater than that the width. The area is 60m^2. Please help me find the dimensions of the width and length. Thank you in advance for your help?
Strange, I answered this question, but it has disappeared.
It shows up in the "related questions" below, however.
How very odd
width = x
length = x+4
x(x+4) = 60
x^2 + 4x - 60 = 0
(x+10)(x-6) = 0
x = 6, or x = -10, the last answer makes no sense
width = 6
lenth = 10
This time is showed up. Thank you very much Reiny.
To find the dimensions of the width and length of the table, we can set up a system of equations based on the given information.
Let's assume the width of the table is "w" meters. According to the problem, the length of the table is 4 meters greater than the width, so we can say the length is "w + 4" meters.
The formula for the area of a rectangle is given by the equation:
Area = Length × Width
From the problem, we know that the area is 60m^2. So we can write:
60 = (w + 4) × w
Now, we can solve this equation to find the value of "w" and then find the length.
To solve the equation quadratic equation, we need to rearrange it to the standard quadratic form:
w^2 + 4w - 60 = 0
This equation is quadratic, so we can solve it using factoring, completing the square, or using the quadratic formula. Let's use factoring to solve it.
(w + 10)(w - 6) = 0
Now we have two possible values for the width: w = -10 or w = 6.
Since the width of the table cannot be negative, we discard the negative value and conclude that the width of the table is 6 meters.
To find the length, we use the equation we set up earlier:
Length = w + 4
Substituting the value of w, we get:
Length = 6 + 4 = 10 meters
So, the dimensions of the table are:
Width = 6 meters
Length = 10 meters
I hope this explanation helps you understand how to find the dimensions of the table!