a minor league baseball team plays 95 games in a season, if the team won 14 more than twice as they lost, how many wins and looses did the team have?
W = 2L + 14
95 = L + 2L + 14
95 = 3L + 14
95 - 14 = 3L
81 = 3L
27 = L
To find the number of wins and losses for the minor league baseball team, we can set up a system of equations based on the information given.
Let's say the number of wins is represented by W and the number of losses is represented by L.
We know that the team played 95 games, so the total number of games is the sum of wins and losses: W + L = 95.
We are also given that the team won 14 more than twice as many games as they lost. Mathematically, this can be represented as: W = 2L + 14.
Now we can solve the system of equations to find the values of W and L.
Substitute the value of W from the second equation into the first equation:
(2L + 14) + L = 95.
Simplifying the equation gives: 3L + 14 = 95.
Subtract 14 from both sides: 3L = 81.
Divide both sides by 3: L = 27.
Now substitute the value of L back into the second equation to find W:
W = 2(27) + 14 = 54 + 14 = 68.
Therefore, the minor league baseball team had 68 wins and 27 losses in the season.