After a shipwreck, a solid steel spoon lies at the bottom of the ocean, 5.75km below the surface. What's the water pressure at that depth? Find the fractional volume change in the spoon due to compression forces.

To find the water pressure at a certain depth in the ocean, you can use the hydrostatic pressure formula:

P = ρgh

Where:
P is the pressure
ρ (rho) is the density of water
g is the acceleration due to gravity
h is the depth

First, we need to determine the values of the variables in the formula. The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s². The depth in this case is 5.75 km, but we need to convert it to meters.

1 km = 1000 meters

So, 5.75 km is equal to 5.75 × 1000 = 5750 meters.

Now, let's calculate the water pressure:

P = ρgh
P = 1000 kg/m³ × 9.8 m/s² × 5750 meters
P ≈ 56,050,000 Pascal

Therefore, the water pressure at a depth of 5.75 km below the surface is approximately 56,050,000 Pascal.

To find the fractional volume change in the spoon due to compression forces, we need to divide the change in volume by the initial volume. However, we do not have enough information about the spoon's characteristics to determine its exact volume change.