object moving w/ speed 1.27m/s rolls off a cliff and hits water .75m from end of cliff. how high above water is the cliff??

not sure what to do here

IT depends on the direction it was rolling. If it was rolling horizontal, its initial vertical veloicty was zero, and the initial horizontal veloicty was as given.

Assuming it was horizontal.
Horizontal
d=vt
.75=1.27 t solve for t, this is the time in the air.
Vertical
h=1/2 g t^2 put in t, and solve for h.

To determine the height of the cliff, we can use the kinematic equations of motion for an object in free fall. Let's break down the problem step by step:

Step 1: Identify the known values
- The horizontal distance from the edge of the cliff to the point of impact is 0.75 meters.
- The initial speed of the object rolling off the cliff is 1.27 m/s.

Step 2: Identify the unknown value
- The height of the cliff above the water is what we need to find.

Step 3: Choose the appropriate equation
We'll use the kinematic equation that relates the horizontal distance, initial velocity, and time of flight of the object:
- Horizontal distance (d) = initial velocity (v) × time (t) + 0.5 × acceleration (a) × t^2

In this case, the horizontal distance is given, the acceleration is due to gravity (approximately 9.8 m/s^2), and we can assume that there is no horizontal acceleration.

Step 4: Solve for time
Since there is no horizontal acceleration, we can use the equation: horizontal distance (d) = initial velocity (v) × time (t)
Therefore, time (t) = horizontal distance (d) / initial velocity (v).

Substituting the values we have: t = 0.75 m / 1.27 m/s.

Step 5: Calculate time
Now, plug in the values and determine the time it takes for the object to hit the water:
t = 0.75 m / 1.27 m/s ≈ 0.591 sec (rounded to three decimal places).

Step 6: Calculate the height of the cliff
Using the time calculated, we can determine the height (h) of the cliff above the water using the equation:
h = 0.5 × a × t^2, where a is the acceleration due to gravity.

Substituting the values we know: h = 0.5 × (9.8 m/s^2) × (0.591 sec)^2.

Step 7: Calculate the height
Calculating this, we find that the height of the cliff above the water is approximately 1.719 meters (rounded to three decimal places).

Therefore, the height of the cliff above the water is approximately 1.719 meters.