how do we calculate the height of a falling ball with a mass of 0.5kg and a velocity of 10m/s.
Unlike your previous post, there is no way to solve this problem. Maybe the ball was thrown from a height of 10km with a velocity of 10m/s
Force=mass*accelaration
F=ma
Soryr. I misread question. wrong.
when a constan force 15 N at an angle of 60 degree with the direction of motion causes a body to move a distance of 10 m calculate the work done by the force.
To calculate the height of a falling ball, you can use the principle of conservation of mechanical energy. The mechanical energy of the ball is a combination of its potential energy (due to its height above the ground) and its kinetic energy (due to its motion).
The formula to calculate the potential energy (PE) is given by:
PE = m * g * h
Where:
m = mass of the ball (0.5kg)
g = acceleration due to gravity (approximately 9.8 m/s²)
h = height
The formula to calculate the kinetic energy (KE) is given by:
KE = (1/2) * m * v²
Where:
m = mass of the ball (0.5kg)
v = velocity of the ball (10 m/s)
At the highest point of the ball's trajectory, it momentarily comes to rest (velocity becomes zero). This means that all of the initial kinetic energy is converted into potential energy. Setting the potential energy equal to the kinetic energy, we have:
PE = KE
m * g * h = (1/2) * m * v²
Simplifying and solving for h:
h = (1/2) * v² / g
Now, substitute the given values:
h = (1/2) * (10 m/s)² / 9.8 m/s²
h = (1/2) * 100 m²/s² / 9.8 m/s²
h = 50 m²/s² / 9.8 m/s²
h = 5.1 meters
Therefore, the height of the falling ball is approximately 5.1 meters.