A rocket expels gases at a rate of 1.30 x 10^3 kg/s with a speed of 3.00 x 10^4 m/s. What is the force
exerted on the rocket?
For
Vex = velocity of the exhaust gases
g = acceleration due to gravity
w = the flow rate of the exhaust gases
F = the thrust exerted on the rocket
Vex/g = F/w or F = wVex/g
3.9x10^7
Solve a rocket expell gas at the rate of 0 .2kg/s if the force produced by the rocket is 15N what is the velocity with which the gas is expelled
To determine the force exerted on the rocket, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, the action is the expelling of gases by the rocket, and the reaction is the force exerted on the rocket.
To calculate the force, we need to multiply the mass of the expelled gases by their velocity. The mass rate of expulsion is given as 1.30 x 10^3 kg/s, and the velocity of the expelled gases is given as 3.00 x 10^4 m/s.
The formula to calculate force is:
Force = mass x velocity
Plugging in the given values:
Force = (1.30 x 10^3 kg/s) x (3.00 x 10^4 m/s)
Now, let's perform the calculation:
Force = (1.30 x 3.00) x (10^3 x 10^4) kg m/s^2
Simplifying further:
Force = 3.90 x 10^3 x 10^7 kg m/s^2
Using the product of powers rule:
Force = 3.90 x 10^10 N
Therefore, the force exerted on the rocket is 3.90 x 10^10 N.
To get this answer, you need to multiply the mass rate of expulsion of the rocket's gases by the velocity at which they are expelled. Remember to pay attention to the units and perform the necessary calculations.
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