Physics

A lump of clay with a mass of 5.0 ! 10-2 kg is thrown toward a wall with a velocity of 3.0 m/s. The
clay bounces off the wall with a velocity of #0.5 m/s. What is the impulse on the clay?

If the clay in the previous problem impacted the wall for 5.0 ms, what was the average force on the
clay?

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  1. Impulse equals momentum change
    = 3.5 m/s*5*10^-2 kg = 0.175 kg m/s

    Divide that by 0.005 s for the average force, in newtons.

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  2. -0.16m/s

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