What is the magnitude of the earth's gravitational field at sea level?
9.81 m/s^2
It is also called the acceleration pf gravity, g.
The magnitude of the Earth's gravitational field at sea level is approximately 9.8 meters per second squared (m/s²).
To find the magnitude of the Earth's gravitational field at sea level, we can use the equation:
g = G * M / R^2
where:
g is the magnitude of the gravitational field
G is the gravitational constant (approximately 6.67430 × 10^-11 m^3 kg^-1 s^-2)
M is the mass of the Earth (approximately 5.972 × 10^24 kg)
R is the radius of the Earth (approximately 6.371 × 10^6 m)
Plugging in these values, we get:
g = (6.67430 × 10^-11 m^3 kg^-1 s^-2) * (5.972 × 10^24 kg) / (6.371 × 10^6 m)^2
Simplifying the equation, we find:
g ≈ 9.81 m/s^2
Therefore, the magnitude of the Earth's gravitational field at sea level is approximately 9.81 m/s^2.