A diagonal of a rectangle measures 61cm. The width of the rectangle is 11cm. Find the length of the rectangle.
This is the case for the Pythagorean Theorem!
a^2 + b^2 = c^2
11^2 + b^2 = 61^2
121 + b^2 = 3721
b^2 = 3721 - 121
b^2 = 3600
b = 60
The ages of two children are 11 and 8years.In how many years time wil the product of their ages be 208
To find the length of the rectangle, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the diagonal in this case) is equal to the sum of the squares of the other two sides.
In this problem, the width of the rectangle is given as 11 cm, which represents one of the sides of the right-angled triangle. Let's assume the length of the rectangle as 'L', which represents the other side of the triangle.
Using the Pythagorean theorem, we have:
Diagonal^2 = Width^2 + Length^2
Substituting the given values:
61^2 = 11^2 + L^2
3701 = 121 + L^2
Now, let's solve for L:
L^2 = 3701 - 121
L^2 = 3580
Taking the square root of both sides, we get:
L = √3580
L ≈ 59.83 cm (rounded to 2 decimal places)
Therefore, the length of the rectangle is approximately 59.83 cm.