Janet jumps off a high diving platform with a horizontal velocity of 2.89m/s and lands in the water 1.5s later.
How high is the platform? The acceleration of gravity is 9.8m/s2
Answer in units of m
How far from the base of the platform does she land?
Answer in units of m
Why are you taking this class if you hate it?
To find the height of the diving platform, we can use the equation of motion:
h = (1/2) * g * t²
Where:
h = height of the platform
g = acceleration due to gravity (9.8 m/s²)
t = time taken to reach the surface of the water (1.5 s)
Substituting the values into the equation, we get:
h = (1/2) * 9.8 * (1.5)²
Calculating this, we find:
h ≈ 11.025 m
Therefore, the height of the platform is approximately 11.025 meters.
To find how far from the base of the platform she lands, we can use the formula for horizontal distance:
d = v * t
Where:
d = horizontal distance from the base of the platform
v = horizontal velocity (2.89 m/s)
t = time taken to land (1.5 s)
Substituting the given values into the equation, we get:
d = 2.89 * 1.5
Calculating this, we find:
d ≈ 4.335 m
Therefore, Janet lands approximately 4.335 meters from the base of the platform.