PLEASE HELPPP!
An ice skater hits a patch of rough ice. The rough patch has a kinetic coefficient of friction with her skates of 0.13. The skater's mass is 51 kg. She passes over the rough patch in 0.55 s. What impulse does the rough patch of ice give her?
M*g*0.13*0.55 kg*m/s
To find the impulse experienced by the skater, we need to use the equation:
Impulse = Force × Time
Impulse is the change in momentum, which can be calculated using the formula:
Impulse = Mass × Change in Velocity
To find the change in velocity, we first need to calculate the force of friction using the equation:
Force = Kinetic Coefficient of Friction × Normal Force
The normal force is the force exerted by the rough patch of ice on the skater, which is equal to the skater's weight (mg). Therefore:
Normal Force = Mass × Acceleration due to Gravity
Substituting this back into the force equation, we have:
Force = Kinetic Coefficient of Friction × (Mass × Acceleration due to Gravity)
Now, we can substitute the force into the impulse equation and solve for impulse:
Impulse = (Kinetic Coefficient of Friction × Mass × Acceleration due to Gravity) × Time