A monatomic ideal gas with a pressure of 1.39x10^5 Pa and has a volume change of 260 L to a volume of 39.0 L. the second pressure is 3.28x10^6. How much work is done?

To calculate the work done by the gas, you can use the formula:

Work = -P(V2 - V1)

where:
- Work is the work done by the gas
- P is the pressure of the gas
- V1 is the initial volume of the gas
- V2 is the final volume of the gas

Given:
- P1 = 1.39x10^5 Pa
- V1 = 260 L
- V2 = 39.0 L
- P2 = 3.28x10^6 Pa

Substituting the given values into the formula, we can calculate the work:

Work = -P(V2 - V1)
= -(P2)(V2 - V1)

Calculating:

Work = -(3.28x10^6 Pa)(39.0 L - 260 L)

First, subtract the volumes:

Work = -(3.28x10^6 Pa)(-221.0 L)

Then, multiply the pressure and volume difference:

Work = (3.28x10^6 Pa)(221.0 L)
= 724,680,000 J

Therefore, the work done by the gas is approximately 724,680,000 Joules.