Evaluate the integral
∫ x/(x+1)^2+4 dx
use partial fractions:
x/(x+1)^2 + 4
= 1/(x+1) - 1/(x+1)^2 + 4
Integral is just
ln(x+1) + 1/(x+1) + 4x
∫ x/(x+1)^2+4 dx
x/(x+1)^2 + 4
= 1/(x+1) - 1/(x+1)^2 + 4
Integral is just
ln(x+1) + 1/(x+1) + 4x