If you decrease the pressure on the equilibrium mixture represented below, which direction would you expect the equilibrium to shift?

C3H8(l) + 5O2(g) 4H2O(g) + 3CO2(g)

You need to learn to place arrows; otherwise we don't know the difference between products and reactants.

An increase in pressure moves the reaction to the side with the fewer moles of gas. Although it makes no difference in this problem, I would argue that propane (C3H8) is not a liquid. The boiling point is listed as -42 celsius.