e^x-2-12^2x+3=0
You have a -2 and a +3 in that equation. Why don't you combine them? Or is (x-2) supposed to be an exponent of e?
If you are only studying algebra, I am surprised that they are teaching you to use e = 2.71828...
You should use parentheses to clarify what the exponents are in your equation.
In any case, it appears to be a transcendental equation that will have to be solved by graphing or iteration.
e^(x-2)-12^(2x+3)=0
Class is a college level math prep.
Sorry for being incomplete in the post.
To solve the equation e^x - 2 - 12^(2x+3) = 0, one way to proceed is by using a numerical method like the Newton-Raphson method or a calculator. However, if you are looking for analytical solutions, it is not straightforward to solve for x algebraically.
If you want to find an approximate solution using a numerical method, you can use the following steps:
1. Rearrange the equation: e^x - 2 = 12^(2x+3)
2. Define a function f(x) = e^x - 2 - 12^(2x+3)
3. Choose an initial guess for x, denoted as x0.
4. Use an iterative method like the Newton-Raphson method to refine the initial guess until a desired level of accuracy is achieved.
If you do not have access to numerical methods or a calculator, you may want to use an online graphing calculator or software to plot the equation. By observing the graphical representation, you may be able to estimate the approximate values of x where the equation equals zero.
Keep in mind that for more complicated equations, it might not always be possible to find exact analytical solutions, and numerical methods become essential.