If a hook exerts a force of .001N on the ceiling, how much force does the ceiling exert on the hook?
To determine how much force the ceiling exerts on the hook, we can apply Newton's third law of motion which states that for every action, there is an equal and opposite reaction. In simpler terms, the force exerted by the hook on the ceiling is equal in magnitude but opposite in direction to the force exerted by the ceiling on the hook.
In this case, if the hook exerts a force of 0.001N on the ceiling, we can conclude that the ceiling exerts a force of 0.001N on the hook in the opposite direction. The force exerted by the ceiling on the hook is also 0.001N.
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. This means that the force exerted by the hook on the ceiling is equal in magnitude and opposite in direction to the force exerted by the ceiling on the hook.
Therefore, the force exerted by the ceiling on the hook is also 0.001N, but in the opposite direction.