Lewis dot of free radical cf2cl and hoco

To draw Lewis dot structures for molecules, follow these steps:

1. Count the total number of valence electrons for each atom in the molecule.
- Carbon (C) has 4 valence electrons.
- Fluorine (F) has 7 valence electrons.
- Hydrogen (H) has 1 valence electron.
- Oxygen (O) has 6 valence electrons.
- Chlorine (Cl) has 7 valence electrons.

2. Determine the central atom by finding the atom with the lowest electronegativity that is capable of forming multiple bonds if necessary.
- In CF2Cl, carbon is the central atom since it is less electronegative than fluorine and chlorine.
- In HOCO, carbon is also the central atom.

3. Place the atoms in the structure by connecting them with single bonds.
- In CF2Cl, connect carbon (C) to two fluorine atoms (F) with single bonds and one chlorine atom (Cl) with a single bond:
F-Cl
- In HOCO, connect carbon (C) to one hydrogen atom (H) with a single bond and one oxygen atom (O) with a double bond:
H-C=O

4. Distribute the remaining electrons around the atoms, starting with the outer atoms. Add lone pairs to satisfy the octet rule, except for hydrogen, which only needs 2 electrons.
- In CF2Cl, you have 22 valence electrons. Distribute them as follows:
F-Cl
| |
:.. ..
:. .
:.:

Each fluorine and chlorine atom already has 8 electrons due to their single bonds. Complete the octet for carbon by adding 4 lone pairs around it:
F-Cl
| . |
:. ..:
:.:

- In HOCO, you have 16 valence electrons. Distribute them as follows:
H-C=O

The carbon atom has 2 electrons from its single bond, and the oxygen atom already has 6 electrons from its double bond. Complete the octet for carbon and hydrogen by adding 4 lone pairs around carbon and 1 lone pair around hydrogen:
H-C=O
. .
.. ..
:.:
. .

These structures represent the Lewis dot structures for the free radicals CF2Cl and HOCO.