f(x) = 5x^2 - 35x

I converted ^ that equation to..
5x^2-35x = 0

How do I go about from here to determine the zeros and the y intercept?

5x(x-7)=0 gives zeroes.

y intercept is when x is zero, so compute f(x) in each case.

Thanks so much!

To determine the zeros and the y-intercept of the equation 5x^2 - 35x = 0, we can use factoring and the quadratic formula.

Step 1: Factor out the common term, x:

x(5x - 35) = 0

Step 2: Set each factor equal to zero and solve for x:

x = 0 or 5x - 35 = 0

For x = 0, we have one zero.

Step 3: Solve the equation 5x - 35 = 0:

5x = 35
x = 35/5
x = 7

So, the other zero is x = 7.

To find the y-intercept, substitute x = 0 into the original equation:

f(0) = 5(0)^2 - 35(0)
f(0) = 0

Therefore, the y-intercept is 0.

In summary, the equation 5x^2 - 35x = 0 has two zeros at x = 0 and x = 7, and the y-intercept is at (0, 0).