A 116.9 g sample of nitric acid solution that is 70.0% HNO3 contains how many moles of HNO3? how did you get the answer
You must not look at your posts. The original was answered hours ago.
http://www.jiskha.com/display.cgi?id=1323115346
is the answer 1.29888 moles?
To find the number of moles of HNO3 in the solution, we first need to calculate the mass of HNO3 in the sample.
Step 1: Convert the percentage concentration to a decimal: 70.0% = 0.700
Step 2: Multiply the mass of the sample by the decimal concentration to get the mass of HNO3:
Mass of HNO3 = 116.9 g × 0.700 = 81.83 g
Step 3: Determine the molar mass of HNO3. Nitric acid (HNO3) has a molar mass of:
1 atom of H (1.01 g/mol) + 1 atom of N (14.01 g/mol) + 3 atoms of O (16.00 g/mol) = 63.01 g/mol
Step 4: Calculate the number of moles of HNO3 by dividing the mass of HNO3 by the molar mass:
Number of moles = Mass of HNO3 / Molar mass of HNO3
Number of moles = 81.83 g / 63.01 g/mol
Using a calculator, we find that the number of moles of HNO3 in the 116.9 g sample is approximately 1.299 moles.