What is the mass percent oxygen in the compound NaNO3?

(3*atomic mass O/molar mass NaNO3)*100 =

To find the mass percent of oxygen in the compound NaNO3, we need to know the molar mass of the compound first.

The molar mass of NaNO3 can be calculated by adding up the atomic masses of all its constituent elements. The atomic mass of sodium (Na) is 22.99 g/mol, nitrogen (N) is 14.01 g/mol, and oxygen (O) is 16.00 g/mol.

So, the molar mass of NaNO3 = (1 * 22.99) + (1 * 14.01) + (3 * 16.00) = 85.00 g/mol.

Next, we need to determine the mass of oxygen in one mole of NaNO3. Since there are three oxygen atoms in one mole of NaNO3, the mass of oxygen is 3 * 16.00 = 48.00 g/mol.

To calculate the mass percent of oxygen, divide the mass of oxygen by the molar mass of NaNO3 and multiply by 100:

Mass percent of oxygen = (48.00 g/mol / 85.00 g/mol) * 100 = 56.47%.

Therefore, the mass percent of oxygen in NaNO3 is approximately 56.47%.