The solubility of solid Ce(IO3)3 in a 0.20 M KIO3 solution is 4.4 10-8 mol/L. Calculate Ksp.
To calculate the solubility product constant (Ksp) for Ce(IO3)3, we need to know the concentration of each ion in the solution.
The balanced equation for the dissociation of Ce(IO3)3 is:
Ce(IO3)3(s) ↔ Ce3+(aq) + 3IO3-(aq)
From the given information, we know that the solubility of Ce(IO3)3 is 4.4 x 10^-8 mol/L. This means that the concentration of Ce3+ ions in the solution is also 4.4 x 10^-8 mol/L.
Since Ce(IO3)3 dissociates into 1 Ce3+ ion and 3 IO3- ions, the concentration of IO3- ions can be calculated by multiplying the concentration of Ce3+ ions by 3:
Concentration of IO3- ions = 3 x 4.4 x 10^-8 mol/L = 1.32 x 10^-7 mol/L
Now, we can calculate the solubility product constant (Ksp) using the concentrations of Ce3+ and IO3- ions:
Ksp = [Ce3+][IO3-]^3
Ksp = (4.4 x 10^-8 mol/L)(1.32 x 10^-7 mol/L)^3
Calculating the value:
Ksp = 9.470336 x 10^-34 mol^4/L^4
Therefore, the solubility product constant (Ksp) for Ce(IO3)3 is 9.47 x 10^-34 mol^4/L^4.
To calculate the solubility product constant (Ksp), you need to consider the balanced equation for the dissociation of Ce(IO3)3, which is:
Ce(IO3)3 (s) ⇌ Ce3+ (aq) + 3 IO3- (aq)
The solubility of Ce(IO3)3 is given as 4.4 × 10^(-8) mol/L in a 0.20 M KIO3 solution. This means that at equilibrium, the concentration of Ce3+ ions in the solution is 4.4 × 10^(-8) mol/L.
Now, let's assume that 'x' represents the concentration of IO3- ions in the solution. Since the stoichiometry of the balanced equation is 1:3 (1 Ce3+ ion is formed for every 3 IO3- ions), the concentration of IO3- ions is 3x.
Using these concentrations, we can write the expression for Ksp:
Ksp = [Ce3+] * [IO3-]^3
Substituting the values we obtained, we have:
Ksp = (4.4 × 10^(-8)) * (3x)^3
Now we need to find the value of 'x'. Since we assume that the concentration of IO3- ions is 'x', we can set up an equation based on the initial KIO3 concentration of 0.20 M:
0.20 M * (1 L) = (x + 3x) * (1 L)
Simplifying the equation, we get:
0.20 = 4x
x = 0.20/4
x = 0.05 M
Now we can substitute the value of 'x' into the Ksp expression:
Ksp = (4.4 × 10^(-8)) * (3 * 0.05)^3
Ksp = (4.4 × 10^(-8)) * (0.15)^3
Calculating this, we find:
Ksp = 9.08 × 10^(-11)
Ce(IO3)3 ==> Ce^3+ + 3IO3^-
4.4E-8......4.4E-4...3*4.4E-4
Ksp = (Ce^3+)(IO3^-)^3
Substitute from the ICE curve I did for you and solve for Ksp. Don't forget to cube IO3^-