A pair of complimentary angles have measure x* (star equals degree) and x*(again star equals degree) + 8*. What is the measure of the smaller angle?

the problems looks like x* and x*+8*

AGAIN THE stars stand for degree.
I think the answer is 6, but not sure how.

Complimentary angles add up to 90*. so 90-8=82 and 82/2 (b/c there's 2 x's) is 41. so the two angles are 41 and 49, the smaller one being 41*.

To find the measure of the smaller angle, we can set up an equation using the fact that complementary angles add up to 90 degrees.

Let's represent the smaller angle as x* and the larger angle as x* + 8*.

Since these angles are complementary, the sum of their measures is equal to 90 degrees:

x* + (x* + 8*) = 90*

Simplifying the equation:

2x* + 8* = 90*

Subtracting 8* from both sides:

2x* = 90* - 8*

2x* = 82*

Dividing both sides by 2:

x* = 82* / 2

x* = 41*

Therefore, the measure of the smaller angle is 41 degrees.

To find the measure of the smaller angle in a pair of complementary angles, you need to set up an equation and solve for the value of x.

In this case, you are given that the measures of the two angles are x° and x° + 8°. Since the angles are complementary, their measures should add up to 90°.

So, you can set up the equation: x° + (x° + 8°) = 90°.

Simplifying the equation gives: 2x° + 8° = 90°.

Next, you need to isolate the term with x by subtracting 8° from both sides of the equation: 2x° = 82°.

Finally, divide both sides of the equation by 2 to solve for x: x° = 41°.

Therefore, the measure of the smaller angle is x°, which is equal to 41°. This means the smaller angle measures 41°.