How many moles of HNO(3) are present if 4.20*10^-2 mol of Ba(OH)(2) was needed to neutralize the acid solution?
2HNO3 + Ba(OH)2 ==> 2H2O + Ba(NO3)2
moles Ba(OH)2 = given
moles HNO3 = 2x that
To determine the number of moles of HNO3 present, we can use the stoichiometry of the balanced chemical equation for the neutralization reaction between HNO3 and Ba(OH)2. The balanced equation is:
2 HNO3 + Ba(OH)2 -> Ba(NO3)2 + 2 H2O
From the balanced equation, we can see that 2 moles of HNO3 react with 1 mole of Ba(OH)2. This means that the mole ratio between HNO3 and Ba(OH)2 is 2:1.
Given that 4.20 x 10^-2 moles of Ba(OH)2 were needed to neutralize the acid solution, we can use the mole ratio to find the number of moles of HNO3.
Number of moles of HNO3 = (4.20 x 10^-2 moles Ba(OH)2) x (2 moles HNO3 / 1 mole Ba(OH)2)
Number of moles of HNO3 = 8.40 x 10^-2 moles
Therefore, 8.40 x 10^-2 moles of HNO3 are present in the acid solution.